A 47 0-g golf ball is driven from the with an initial speed of 520 m/s and rises

Question

A 47 0-g golf ball is driven from the with an initial speed of 520 m/s and rises to a height of 24.6 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 8.0 m below its highest point? Consult Conceptual Example 9 in preparation for this problem. The drawing shows a person who, starting from rest at the top of a cliff, swings down at the end of a rope, releases it, and falls into the water below. There are two paths by which the person can enter the water. Suppose he enters the water at a speed of 13.0 m/s via path 1. How fast is he moving on path 2 when he releases the rope at a height of 5.20 m above the water? Ignore the effects of air resistance.

Explanation / Answer

41) 0.5mv1^2 = mgh +0.5mv2^2

0.5*52^2 = 9.8*24.6 +v2^2 / 2

v2 = 47.13 m/s

ii) 0.5*52^2 = 9.8*(24.6-8) +v2^2 / 2

v2 = 48.77 m/s

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