The figure below is a cross-sectional view of a coaxial cable. The center conduc

Question

The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is = 1.20 A out of the page and the current in the outer conductor is = 2.90 A into the page. Assuming the distance d = 1.00 mm, answer the following. Determine the magnitude and direction of the magnetic field at point a. magnitude direction upward Determine the magnitude and direction of the magnetic field at point b. magnitude direction downward

Explanation / Answer

from Ampere's law

B*2*pi*r = uo*Ienclosed

(a)

B*2*pi*d = uo*I1

B*2*pi*1*10^-3 = 4*pi*10^-7*1.2

B = 240 uT   <<<<<<<_---------------answer

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(b)

B*2*pi*3d = uo*(I2 - I1)

B*2*pi*3*1*10^-3 = 4*pi*10^-7*(2.9-1.2)

B = 113.33 uT   <<<<<<<<_---------------answer

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