A 64.7 kg ice skater moving to the right with a velocity of 2.38 m/s throws a 0.

Question

A 64.7 kg ice skater moving to the right with a velocity of 2.38 m/s throws a 0.117 kg snowball to the right with a velocity of 39.2 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice. Answer in units of m/s. A second skater initially at rest with a mass of 61.3 kg catches the snowball. What is the velocity of the second skater after catching the snowball in a perfectly inelastic collision? Answer in units of m/s.

Explanation / Answer

Given :-

m1 = 64.7 kg

m2 = 0.117 kg

Vi = 2.38 m/s

V2,f = 39.2 m/s

1)

m1Vf,1 = (m1 + m2)Vi - m2V2,f

Vf,1 = [(m1 + m2)Vi - m2V2,f] / m1

Vf,1 = [(64.7 + 0.117)*2.38 - 0.117*39.2] / 64.7

Vf,1 = 2.3134 m/s

b)

mVi,1 = 39.2 m/s

m1 = 0.117 kg

m2 = 61.3 kg

m1Vi,1 = (m1 + m2)Vf

Vf = m1Vi,1 / (m1 + m2)

Vf = 0.117*39.2 / (0.117 + 61.3)

Vf = 0.07468 m/s

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