Activity 11 Conservation of Momentum Problems Draw a \"before\" and an \"after p

Question

Activity 11 Conservation of Momentum Problems Draw a "before" and an "after picture for each of these situations below. In all these cases there is no net external force on the system so the total system momentum is conserved. This means that you can use the fact that the total system momentum has to be the same after an interaction as it was before to find the "unknown" quantity in the question. Example: Cart A has a mass of 300 kg and is going to the right at a speed of 0.200 m/s and cart Bhas a mass of 2.00 kg and is going to the left with a speed of o300m/s. They collide and cart A is seen to now be going to the left with a speed of o.100 m/s. What is the velocity of B after the collision? v 0.6 3kg 0.2 3kg 0.1 Pau does not change Past Pau 0.3 Pay 0.15 2kg 03 Ap p 4p 9N avv.A At At 0.1s 1. Now use the example as a model and do the following problems the same way: a. The same two carts as above have the same initial velocities as the example above, but when they hit they stick together, so that the final situation is essentially a big 5.00 kg cart with some final momentum and velocity that you can find.

Explanation / Answer

a)   5V = 3 X 0.2 - 2 X 0.3 = 0

AVERAGE FORCE ON A = [ 0 – 0.6 ] / 0.1= - 6 N

b)         5V = 3 X 0.5 – 2 X 0.1

= 1.5 – 0.2

= 1.3

c)         5 X 0.2 = 3 X – 0.1   + 2VB   

            1 + 0.3 = 2V1  

              VB = 1.3 / 2 = 0.65 m/s [towards the right]

d)

AVERAGE FORCE ON A = [ 0 – 0.6 ] / 0.1= - 6 N     [a]

AVERAGE FORCE ON A = [3 x 0.26 – 3 x 0.5] / 0.1 = - 0.72 / 0.1 = - 7.2 N     [b]

AVERAGE FORCE ON A = [ 3 X ( - 0.1) – 3 X 0.2] / 0.1 = - 9 N      [c]

            Hope this helps !

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