Activities and Due Dates due 1 /28 202-Spring16 . KALK Gradebook 28/2016 09.30 A

Question

Activities and Due Dates due 1 /28 202-Spring16 . KALK Gradebook 28/2016 09.30 AM 44.3/1001/27/2016 11:01 AM Print Calculator Period. Table stion 16 ofl 21 MapA Physics sapling leaming What is the force on the charge located at x 16.00 cm in the figure below given that q- 2.250 C? The other two charges are located at 6.000 cm and 22.00 cm. Take the positive direction as pointing to the right Number - 24 10.00 [em] 20.00 Previous check Answer Next tl Ext us tareers parinersprivary polcy ters of use coneact us help

Explanation / Answer

F=kq1q2/r^2

Force at -2q charge will be attractive due to both the charges but the direction is opposite. So the net direction is towards right.

F = (k*q*2q)[1/(0.06)^2 - 1/(0.1)^2] =2kq^2 * 177.78

=2*9*10^9*(2.25*10^-6)^2*177.78 =16.2 N

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