Question
#1 Please answer the question neatly with steps and show all units, for good rating!
Potentially HelpfurInformation: unev rada 1min -ses L A30kg musis dropped from a height of 5.0m above the end ofs vertical spring whose spring constant is 20Nm. ia How far will ee spring be What is the ehange gravitational energy of the mass? isa What is change in elastic potential energy ofthe spring? agnore any loss of energy in joining of the alass with the end of the spring and ignore the mass of the spring Assante bottom end of the spring is rigidly held in place) An B00kg roller-coaster initially moving at 8 sms eomes down its tracks s distance af300m measured along its tracks, as shown. (a) lf te friction force is an average of80ON far the full run of the track, what will its speed be at the bottom? Assume the vertical drop ofthe trackis 35m and the actual run of the truck is 300m, as showm below, How much work is done by the foree of friction?; by the normal foree?; and by the force of gravity? (Hint: Don't forget that gavity is a conservative force and that fiction is not a conservative force) ve 8.5m's
Explanation / Answer
Ans 1 a) let the spring is compressed to x
now apply energy conseervation we get
mgh = 1/2 k x2
3*9.8*5 1/2*20*x2
x = 3.834m
b) change in gravitational potential energy = mgh = 147J
c) change in spring elastic potential energy = change in gravitational potential energy = mgh = 147J
