The ideal battery in Figure (a) has emf = 7.6 V. Plot 1 in Figure (b) gives the
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Question
The ideal battery in Figure (a) has emf = 7.6 V. Plot 1 in Figure (b) gives the electric potential difference V that can appear across resistor 1 of the circuit versus the current i in that resistor. The scale of the V axis is set by Vs = 20.9 V, and the scale of the i axis is set by is = 3.15 mA. Plots 2 and 3 are similar plots for resistors 2 and 3, respectively. What is the current in resistor 2?
Chapter 27, Problem 028 The ideal battery in Figure (a) has emf E 7.6 V. Plot 1 in Figure (b) gives the electric potential difference V that can appear across resistor 1 of the circuit versus the current i in that resistor. The scale of the Vaxis is set by Vs 20.9 V, and the scale of the i axis is set by is 3.15 mA. Plots 2 and 3 are similar plots for resistors 2 and 3 respectively. What is the current in resistor 2? i (mA) (a) Units Number the tolerance is +/-9%Explanation / Answer
length of 1 div on vertical = 20.9/9
length of 1 div on horizontal = 3.15/6
slope of line 1 = R1 = Vs/Is = 20.9/(3.15*10^-3) = 6635 ohms
slope of line 2 = R2 = (20.9*6/9)/(3.15*10^-3) = 4423.3 ohms
slope of line 3 = R3 = (20.9*3/9)/(3.15*10^-3) = 2211.64 ohms
R1 , R2 are in parallel
R12 = (R1*R2)/(R1+R2) = (6635*4423.3)/(6635+4423.3) = 2654 ohm
R12 & R3 are in series
Req = R12 + R3 = 4865.64 ohms
current I3 = V/Req = 7.6/4865.64 = 0.00156 A
current I2 = V2/R2 = (V - I3*R3)/R2 = (7.6-(0.00156*2211.64))/4423.3 = 0.000938 A
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