A car traveling at 96 m/s slows down at a constant rate of 0.5 m/s^2 by just \"l

Question

A car traveling at 96 m/s slows down at a constant rate of 0.5 m/s^2 by just "letting up on the gas". What was the car's initial speed in m/s? Calculate the distance the car takes to a stop? How long does the car take to come to a full stop? The carton shown in the figure lies on a rough plane titled at an angle beta=22.0^+ to the horizontal with mu_k = 0.12 Draw the free-body diagram showing all forces acting on the carton. Draw directly on the figure above. Determine the acceleration of the carton as it slides down the plane. A hiker throws a ball at an angle of 21.0^+ above the horizontal from a hill 21.0 m high. The magnitudes of the horizontal and vertical components of the velocity are 14.004 m/s and 5.3760 m/s, respectively. Using the information above, what is the initial velocity of the ball? How long will the ball be in the air before it strikes the ground below the hill?

Explanation / Answer

here,

a)

the initial speed of car , u = 96 m/s

b)

accelration , a = - 0.5 m/s^2

let the distance travelled before stopping be s

using third equation of motion

v^2 - u^2 = 2 * a * s

0 - 96^2 = - 2 * 0.5 * s

s = 9216 m

the distance travelled before stopping is 9216 m

c)

let the time taken be t

v = u + a * t

0 = 96 - 0.5 * t

t = 192 s

the time taken to stop is 192 s

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