Hello can you please help with this problem with part A and B (explains why) Tha

Question

Hello can you please help with this problem with part A and B (explains why) Thank you.. A snowboarder coasts on a smooth track that rises from one level to another, If the snowboarder's initial speed is 4 m/s, the snowboarder just makes it to the upper level and comes to rest. With a slightly greater initial speed of 5 m/s, the snowboarder is still moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on the fictional planet Epsilon, where the acceleration due to gravity is less than it is on the Earth. Part A Would the height of a hill on Epsilon that oauses a reduction in speed from 4 m/s to 0 be greater than, less than, or equal to the height of the corresponding hill on Earth? Explain. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Submit My Answers Give Up Part B Consider the hill on Epsilon discussed in part Alfthe initial speed at the bottom of the hill is 5 m/s, wil the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain. Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 character(s) remaining Submit My Answers Give Up

Explanation / Answer

From the question we know that accelaration due to gravity of planet epsilon ( gep) is less than accelaration due to gravity of earth( gearth) . We have an eqution of motion which is V2-U2= 2*g*h .

Where V is the final velocity and U is the intial velocity ans g ia accelaration due to gravity and h is the height .

(A) the intial velocity (U) = 4m/s and final velocity ( V)= 0 m/s substituting in equation we have V2-U2 = 2* gearth *hearth

In planet epsilon the same.eqution canbe written as V2-U2= 2*gepsilon*hepsilon . Since V and U are same in both the planets and comapring equtions we get hepsilon is greater than hearth . Cause gepsilon is less than g earth.

That is in planet epsilon acceleration due to gravity is lesser

Object would come to rest( in our case snowboarder ) after travelling greater distance compared to earth . Hence the height of hill.in epsilon planet has to be greater than height of the hill on earth.

(B)this question compares final velocity of the snowboarder on earth and on the planet epsilon

Using the same eqution of motion V2-U2= 2*g*h .

From part (A) we know that hepsilon > hearth and from the numerical we get info. That gepsilon <gearth. We are here to fimd out the final velocity given the intial velocity as 5m/s

What would be the final velocity on planet epsilon .on planet earth in the same situation the final velocity is 3m/ s.

We have hepsilon from part ( A) is given by Where U= 4m/s and V = 0 m/s . Substituting in equation we get

hepsilon = - 16/ ( 2* gepsilon) ; now we have V is unknown in palnet epsilon and U = 5m/s .

V2- 25= 2* gepsilon*hepsilon = 2* gepsilon *(-16/ 2*gepsilon)

= -16; V2-25= -16 ; V= 3m/ s .

As given in part(B) if we consider the same hill on epsilon with the height hepsilon the final velocity of the object( snow boarder ) remains same as other parameters are constant.

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