1. A proton is moving from south to north at a speed of 400m/s directly towards

Question

1. A proton is moving from south to north at a speed of 400m/s directly towards the side of a long, straight wire that is carrying a current of 5.0A from west to east. The proton is a distance of 30cm away from the wire and the wire is made of copper and has a diameter of 2.00mm.

a) What is the magnitude and direction of the magnetic force on the proton at that location due to the current in the wire? (use north/south/east/west/up/down to describe the direction)

b) If it were an electron instead of a proton, what would be the magnitude and direction of the acceleration of the electron at that location due to the current in the wire? (use north/south/east/west/up/down to describe the direction)

Explanation / Answer

let's start with calculating agnetic field of the wire

B = ( 4pi x 1o^-7) ( 5) / ( 2 pi x 0.3) = (10*-6 )/0.3= 3.33 x 10^ -6 T

a) F = q(v x B) = (1.6 x 10^-19 ) ( 400 x 3.33 x 10^-6 ) = ( 1.6 x 10^-19) ( 13.33 x 10^-4 ) = 21.33 x 10^ -23 N

towards west

b) Acceleration of electron = F/ m = ( 21.33 x 10^ -23)/ ( 9.1 x10 ^-31) = 2.344 x 10^ 8 m/s^2

towards east

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