How much work is required to put the two protons in place (against their mutual
ID: 1543973 • Letter: H
Question
How much work is required to put the two protons in place (against their mutual electric repulsion) inside an alpha particle, assuming the distance between them is 2.0 x 10^-13 cm. Express your answer in eV. Three point charges - 2.0/mu C, 3.0 mu C and 4.0 mu C lie on the vertices of an equilateral triangle of side 2.0m. How much work has been done to establish this configuration? Charge is supplied to the metal dome of a Van de Graff generator by the belt at the rate of 300mu C/s when the potential difference between the belt and the dome is 1.25MV. the dome transfers charge to the atmosphere at the same rate, so the 1.25MV potential difference is maintained. What minimum power is needed to drive the moving belt and maintain the 1.25 MV potential difference? (Difficult)Show that the total work needed to assemble a uniformly charged sphere of total charge Q and radius R is given by 3Q^2/(20 pi epsilon_0R) 113V 6.25kV/m, 0kV/m, 750V, 750V, 1.56kV/m, 375V 750kV R.-RJ 3 WkQ/^R) (o) 0, kQ/r, kQ/rkQ(/a + 1/c - l/b), kQ(/r +1/c -1/ft), kQ/c, kQ/r (ft) 0, kQ/r1, 0.0, *C(l/) - /b), kQ(/r - 1/ft), 0, 0 (c) 0, kQ/r2, 0.2kQ/rkQ(l/a + 2/c-/b), kQ(l/r + 2/c- I/ft), 2kQ/c, 2kQ/r T2J0keV - 9mJ 10. 375VVExplanation / Answer
work don e= K (q) (q) / r
Work done = 9 x 10^ 9 ( 1.6 x 10^-19) ^2/( 2 x 10^-15)
W= 11.52 x 10^-14 J = 7.1902 x 10^5 eV= 720 KeV
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