007 (part 1 of 4) 10.0 points An object with a resistance of 10 2 has 120 V appl

Question

007 (part 1 of 4) 10.0 points An object with a resistance of 10 2 has 120 V applied to it. How much electric current is going through this object? Answer in units of amps. 008 (part 2 of 4) 10.0 points How much power is being produced by the object? Answer in units of W. 009 (part 3 of 4) 10.0 points How much electric energy will be needed to operate this object for 23 h? Answer in units of kWh 010 (part 4 of 4) 10.0 points What is the cost of operating this object for 23 h at a rate of 8.6 cents/kWh? Answer in units of

Explanation / Answer

7) R = 10 ohms ,V = 120 V

I = V/R = 120/10 = 12 A

8) P = IV

P = 12*120 =1440 W

9) t = 23 h

P = IV = Q/t

12*120 = Q/(23*60*60)

Q = 119232000 J

Q = 119232000/746

Q = 159828 kWh

10) total cost = 159828*8.6

= 1374520 $

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