002 12. (6 points) Answer parts a-c. The short sequence within a protein-coding

Question

002 12. (6 points) Answer parts a-c. The short sequence within a protein-coding gene below has great importance and that possible mutations have been identified here in different individuals. You know the effect at the protein level. Indicate ONE possible single- base pair DNA change that could lead to each result. For each patient, write both the wild-type and mutant DNA and protein sequences. AACI N, C, 5" . aat tca ttt ccc aag 5' t+a agt caa 3 3' ggg +tc-matant Dave al Patient A has a missense mutation. - ? N ASN Ser Leu Pro Lysprotin Patient B has a frameshift mutation.7 3/ A control, individual C, has a synonymous (silent) mutation.No Chara

Explanation / Answer

given,

wild type DNA is-    5'....aat tca ttt ccc aag....3'

so wild type RNA will be- 5'....aau uca uuu ccc aag....3'

& wild type protein sequence will be- 5'....asn ser phe pro lys....3'

(a) patient A has missense mutation. as we know in missense mutation single nucleotide change result in codon for different amino acid.

wild type DNA is-    5'....aat tca ttt ccc aag....3'

wild type RNA is- 5'....aau uca uuu ccc aag....3'

wild type protein sequence will be- 5'....asn ser phe pro lys....3'

suppose here nucleotide U in phe codon is changed into A, so

mutant type RNA is- 5'....aau uca uau ccc aag....3'

mutant type DNA will be-      5'....aat tca tat ccc aag....3'

mutant type protein sequence will be- 5'....asn ser tyr pro lys....3'

(b) patient B has frameshift mutation. in which insertion or deletion of a no. of nucleotide DNA sequence cause shift in codon of RNA which cause change in protein sequence.

wild type DNA is-    5'....aat tca ttt ccc aag....3'

wild type RNA is- 5'....aau uca uuu ccc aag....3'

wild type protein sequence will be- 5'....asn ser phe pro lys....3'

suppose here we insert A nucleotide in first codon, so

mutant type RNA will be- 5'....aaa uuc auu ucc cca g....3'

mutant type DNA will be-    5'....aaa ttc att tcc cca g....3'

mutant type protein sequence will be- 5'....lys phe ile ser gln....3'

(c) a control individual C, has a synonymous (silent) mutation. as we know in silent mutation, change in one nucleotide of DNA at one position produce same amino acid so DNA do not have an observable effect on the organism's phenotype.

wild type DNA is-    5'....aat tca ttt ccc aag....3'

wild type RNA is- 5'....aau uca uuu ccc aag....3'

wild type protein sequence will be- 5'....asn ser phe pro lys....3'

suppose here C nucleotide in pro codon is mutated into A nucleotide, so

mutant type DNA is-    5'....aat tca ttt cca aag....3'

mutant type RNA is- 5'....aau uca uuu cca aag....3'

mutant type protein sequence will be- 5'....asn ser phe pro lys....3'

Related Questions

Navigate

• Browse (All)
• Browse
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.