Suppose the roller coaster car (mass = 220 kg) in the picure shown passes point

Question

Suppose the roller coaster car (mass = 220 kg) in the picure shown passes point A (h1 = 40.0) with a speed of 7.00 m/s if friction does -17 kJ of work on the car going from A to C (h3 = 20.0 m) use conservation of energy of energy to determine the speed of the car at point C. If the total distance traveled is 120.0 m. determine the average force of friction.

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Explanation / Answer

Mass m = 220 kg

Speed Vi = 7.00 m/s

h1 = 40.0 m

h3 = 20.0 m

Work Wf = -17 kJ

The total distance travelled is 120.0 m.

Wg + Wf = ½ m Vf2 - ½ m Vi2

(Wg = mg ((h1-h3)

(200kg) (9.81m/sec2) (40-20) +( – 17000 J) = 0.5 x 220 kg (V2 – 72)

Speed of car at point C, Vf = 15.84 m/sec

...............................................................................................................................................................

Average force of friction, Ff = - Work done/ distance travelled

Ff = W / d

Ff = 17000 J/ 120

Ff   = - 141.66 N

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