What is the acceleration due to gravity at an altitude of 1.00 times 10^6 m abov

Question

What is the acceleration due to gravity at an altitude of 1.00 times 10^6 m above the earth's surface? 3.99 m/s^2 5.00 m/s^2 7.32 m/s^2 9.80 m/s^2 6.77 m/s^2 Two point masses m and M are separated by a distance d. If the separation d remains fixed and the masses are increased to the values 2m and 2M respectively, how does the gravitational force between them change? The force will be half as great. The force will be one-forth as great. The force will be two times as great. The force will be four times as great. It is impossible to determine without knowing the numerical values of m, M, and d.

Explanation / Answer

19.) gravity at height h

g' = g(1-2h/R)

g' = 9.81(1-2*10^6/6.38*10^6)

g' = 6.77 m/s^2

2.) the force will be 4 times

F = Gm1m1/r^2 = 4GmM/d^2

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.