A 3.25 g bullet picks up an electric charge of 1.65 C as it travels down the bar

Question

A 3.25 g bullet picks up an electric charge of 1.65 C as it travels down the barrel of a rifle. It leaves the barrel at a speed of 407 m/s traveling perpendicular to the earth’s magnetic field, which has a magnitude of 5.50×104 T .

Part A

Calculate the magnitude of the magnetic force on the bullet.

Express your answer with the appropriate units.

Part B

Calculate the magnitude of the bullet’s acceleration due to the magnetic force at the instant it leaves the rifle barrel.

Express your answer with the appropriate units.

Explanation / Answer

Part A )

given

m = 3.25 g

= 0.00325 kg

q = 1.65 C

= 1.65 X 10-6 C

V = 407 m/s

B = 5.50 X 104 T

using F = q V B

F = 1.65 X 10-6 X 407 X 5.50 X 104

F = 3.69 X 10-7 N

Part B )

using F = m a

a = F / m

a = 3.69 X 10-7 / 0.00325

a = 1.135 X 10-4 m/sec2  

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