The figure below is a cross-sectional view of a coaxial cable. The center conduc

Question

The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I_1 = 1.08 A out of the page and the current in the outer conductor is I_2 = 3.08 A into the page. Assuming the distance d = 1.00 mm, answer the following. Determine the magnitude and direction of the magnetic field at point a. Determine the magnitude and direction of the magnetic field at point b.

Explanation / Answer

Given

I1 = 1.08 A out of the plane , I2 = 3.08 A in to the plane

we know that the magnetic field is B = mue not *i1/2pir
a)

       B at a is , B_a = 4pi*10^-7*1.08/(2pi*1*10^-6) T = 0.216 T= 216 mT = 216000*10^-6 T
direction is out of the plane

b)

at point b is

       B1 _b = mue not*I1/2pir1

       B2 = mue not*I2/2pir2

B1_b = 4pi*10^-7*1.08/(2pi*d) = 0.216 T out of the plane

B2_b = mue not*I2/2pir2 = 0.072 T the direction is out ofplane the

net field at point b is

B_b = B2_a+B2_b = 0.216-0.072 T = 0.144 T = 144000*10^-6 T

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