Now, in Texas, let\'s think there is a compass showing the lab\'s door in the no

Question

Now, in Texas, let's think there is a compass showing the lab's door in the north as expected. When I let the compass touched the wire with a current flowing from the door direction to windows from the bottom, the compass turns and makes an angle of 90 with the wire. Obviously the magnetic field of the wire is bigger than the Earth's magnetic field in the vicinity of the wire. Prove this observation with calculations of your own. When the compass touches the wire, take the distance between them as 0.5 cm, and the current flowing through the wire is 10 A.

Explanation / Answer

magnetcif field due to current carrying wire is

B = uoI/2piR

uo is permability COnstant = 4pi *10^-7 H/m

I is current = 10 A

R si the Distance

so

B = (4pi *10^-7 * 10)/(2*3.14 * 0.005)

B = 4*10^-4 Tesla = 4 Gauss

actual magnetic field is 1G, but here it is 4G so its higher

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