You drag a 30 kg box along the floor by pulling it with a rope that is at a 35o

Question

You drag a 30 kg box along the floor by pulling it with a rope that is at a 35o angle above the horizontal. There is a coefficient of kinetic friction of 0.2 between the box and the floor, and the box accelerates at 1.0 m/s2. What is the tension in the rope?

You drag a 30 kg box along the floor by pulling it with a rope that is at a 35o angle above the horizontal. There is a coefficient of kinetic friction of 0.2 between the box and the floor, and the box accelerates at 1.0 m/s2. What is the tension in the rope?

You drag a 30 kg box along the floor by pulling it with a rope that is at a 35o angle above the horizontal. There is a coefficient of kinetic friction of 0.2 between the box and the floor, and the box accelerates at 1.0 m/s2. What is the tension in the rope?

Explanation / Answer

equation of motion:

T - mgsin35 - mgu = ma

or, T = m( gsin35 + gu + a) = 30(9.8sin35 + 9.8x.02 + 1.0) = 257.43 N

the tension in the rope IS 257.43N

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