In the absence of air resistance, a projectile is launched from and returns to g

Question

In the absence of air resistance, a projectile is launched from and returns to ground level. It follows a trajectory similar to that shown in the figure below and has a range of 21 m. Suppose the launch speed is doubled, and the projectile is fired at the same angle above the ground. what is the new range? R = A major-league pitcher can throw a baseball in excess of 49.6 m/s, If a ball is thrown horizontally at this speed, how much will it drop by time it reaches the catcher who is 18.9 m away from the point of release? m

Explanation / Answer

Here,

as the range is given as

Range = u^2 * sin(2 * theta)/g

u is the launch speed and theta is the launch angle

for doubling the speed , range will be 4 timmes

hence , Range = 4 * 21

Range = 84 m

the range is 84 m

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