Greetings, please help me solve problems 3a, 3b, 3c, and \"BONUS\". I would grea
ID: 1536063 • Letter: G
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Greetings, please help me solve problems 3a, 3b, 3c, and "BONUS". I would greatly appreciate it if you showed your work step by step. Thank you & have a nice day!
3. You (mass 500 kg) are standing on a "bathroom scale" while riding in an elevator. A friend is standing nearby in the elevator (but not standing on the scale), and in some of the cases below, the friend applies an upward or downward force on you. NOTE: A "bathroom scale always reads the magnitude of the normal force of the floor on you. For the following questions that ask for a scale reading. lease provide normal force with MRS ce units, NOT mass or a. (2 pts. The elevator is ascending at constant speed of 1.000 m/s, and your friend is not touching you. What is the reading on the scale? Show your work. b. (4 pts.) While the elevator is acceleraring upward at constant acceleration of 100 m/s your nearby friend simultaneously pushes vertically downvward on your shoulders with 100. N of force. What is the reading on the scale? Show your work. c (3 pts.) At a time when the scale reading is 445 N, and your friend is not touching you, what are the magnitude and direction of the elevator's acceleration? Show your work. BONUS: (+1 pt) The elevator cable snaps, and the elevator (and all of its contents fall freely. If your friend is not touching you during this time, what is the reading on the scale? (Thought question INOT for credit: How is it possible that some scales are labeled in kilograms mass units) instead of newtons or pounds (force units)? What calculation or conversion has the scale manufacturer performed. and what assumptions have they made?)Explanation / Answer
(a)
when elevator is ascending upwards,
F = N - mg
N = m*(g + a)
as given constant speed. so, a = 0
so reding of scale = m*g = 50*9.8
F = 490 N
()
when elevator is accelerating upwards,
reading of scale is
F = m*(g + a) - 100
F = 50*(9.8 + 1) - 100
F = 440 N
(c)
F = m*(g - a)
445 = 50*(9.8 - a)
a = 0.9 m/s^2 (downwards)
(d)
in case of free falling,
reading of scale = 0
(weightlessness)
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