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An electron experiences a force F = (4.5 i 2.8 j )×1013N when passing through a

ID: 1535540 • Letter: A

Question

An electron experiences a force

F=(4.5i2.8j)×1013N when passing through a magnetic field B =(0.55T)k.

Part A

Determine the electron's velocity.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

An electron experiences a force

F=(4.5i2.8j)×1013N when passing through a magnetic field B =(0.55T)k.

Part A

Determine the electron's velocity.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

vx, vy =

Explanation / Answer

F = (4.5 i- 2.8 j)*10^-13 N

V = (0.55T)k

charge of electronq = -1.6*10^-19 C

F = q(vxB)

(4.5 i- 2.8 j)*10^-13 = (-1.6*10^-19)((vxi +vyj)x(0.55k))

(4.5 i- 2.8 j)*10^-13 = (-1.6*10^-19*0.55)(-vxj +vyi)

comparing with i and j components

-2.8*10^-13 = 1.6*10^-19*0.55*vx

vx = -3.2*10^6 m/s

4.5*10^-13 = -1.6*10^-19*0.55*vy

vy =- 5.1*10^6 m/s

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