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Any help with both these questions will be much appreciated. Thanks! The velocit

ID: 1534600 • Letter: A

Question

Any help with both these questions will be much appreciated. Thanks!

The velocity of the wind relative to the water is crucial to sailboats. Suppose a sailboat is in an ocean current that has a velocity of 2.7 m/s in a direction 33 degree east of north relative to the Earth. It encounters a wind that has a velocity of 4.9 m/s in a direction of 48 degree south of west relative to the Earth. v_1 = 2.7 m/s v_2 = 4.9 m/s a_1 = 33 degree a_2 = 48 degree What is the magnitude of the velocity of the wind relative to the water m/s? What is the angle of the velocity of the wind relative to the water degrees S of W?

Explanation / Answer

let east be +x axis

a)

velocity of wind with resect water = velocity of wind with respect to ground - velocity of water with resoect to ground

= ( -4.9*cos(48) i - 4.9*sin(48) j) - (2.7*sin(33)i + 2.7*cos(33)j )

= (-4.75 i - 5.90 j) m/s

|v| = sqrt(4.75^2 + 5.9^2)

= 7.57 m/s <<<<<<<<<------------------Answer

b) direction:

theta = tan^-1(5.9/4.75)

= 51.2 degrees <<<<<<<<<------------------Answer

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