A galvanometer having a resistance of 29.0 Ohm has a 1.00-Ohm shunt resistance i

Question

A galvanometer having a resistance of 29.0 Ohm has a 1.00-Ohm shunt resistance installed to convert it to an ammeter. It is then used to measure the current in a circuit consisting of a 16.0-Ohm resistor connected across the terminals of a 40.0-V battery having no appreciable Internal resistance. What current does the ammeter measure? A What should be the true current in the circuit (that is, the current without the ammeter present)? A By what percentage is the ammeter reading in error from the true current? %

Explanation / Answer

(1) rm=(29*1)/(29+1)= 29/30
Ic= 29/(16+29/31)

= 1.71 A

(2) I=E/R = 29/16
= 1.81 A

(3)
%age = [1 - (1.71/1.81)]*100
About 5.52 % smaller

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.