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Secure I https/www.webassign.net/web/Student/Assignment-Responses/submit?deps156753S6 A m1 5.17-kg block is placed on top of a m2 10.0-kg block (figure)- A horizontal force 4s.0 N is applied The coefficient of kinetic friction between all moving of F surfaces is o.194. to the 10.0 kg block, and the 5.17-kg block is tied to the wan (a) Draw a free body diagram for each block and identify the action-reaction forces between the blocks. (submit a file with a maximum size of 1 Me.) Choose File No file chosen This answer has not been graded yet (b) Determine the tension in the string. (Enter the magnitude only.) Determine the magnitude of the acceleration of the 10.0 kg block. Help? Read

Explanation / Answer

frictional force = 5.17 kg * 9.8 * 0.194 = 9.84 N

frictional force that the ground exerts on the 10 kg block = (5.17 kg + 10 kg) * 9.8 * 0.194 = 28.84 N

Net force on the 10 kg block = 45 - (9.84 N + 28.84 N) = 6.32 N

Net acceleration = 6.32 / 10 = 0.632 m/s2

Tension = 9.84 N

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