Sections 4.1 and 4.2 just have the solubility rules And the equilibrium constant

Question

Sections 4.1 and 4.2 just have the solubility rules And the equilibrium constants. Question 2 is not needed. Everything you need to complete the question is given. I will thumbs up all answers. Thank you

4. Using the information in Sections 4.1 and 4.2, as well as the line of thinking illustrated in question 2 above, predict the outcome when each cation reacts with the four reagents used in the preliminary tests. Complete the reaction table below in your lab notebook prior to coming to the first week of this lab. During the Week 1 lab period, you will characterize the behavior of your four assigned cations with the reagents; the predictions you make now will help you analyze the results you find during Week 1. One cation is done completely for you as an example; the reasoning behind each entry is given as a footnote. You do not need to provide a written explanation for your entries -these are provided as an example of the thinking to be applied when completing this reaction grid. Cation Al3+ Ba2 Cu2+ Fe*+ Mn2+ Ni2+ NaCI Na2SO4 NaOHNH3 (aq) Solid. AgSo, Footnote 1 Footnote 2 Footnote 3 Footnote 4 According to the solubility rules, all chlorides are soluble except silver and lead. Therefore a precipitate expected; appearance (color, etc.) of the precipitate will be noted during the lab period. However, since silver and chloride can form a soluble complex ion, AgCl2, addition of excess chloride dissolve the initially formed precipitate. may actually 2Silver(I) and sulfate form an insoluble compound according to the solubility rules and the Kp data. According to the solubility rules and the Ksp data, AgOH should form; appearance unknown at this time This solid is not expected to dissolve as there is no complex ion involving silver and hydroxide. Since 1.0 M ammoni However if the concentration of ammonia is great, then the soluble complex i precipitate would dissolve. ia is a source of hydroxide ions (see Pre-lab question 3), AgOH is expected to form. on can form and the

Explanation / Answer

Al+3 with NaCl,Na2SO4,NaOH,NH3 on reaction will give AlCl3(s),Al2(SO4)3,Al(OH)3,Al(OH)3 respectively.

Hint:Since 1.0M ammonia solution is a source of hydroxide ions.

Ba+2 withNaCl,Na2SO4,NaOH,NH3 on reaction will give BaCl2,BaSO4,Ba(OH)2,Ba(OH)2

Cu+2 withNaCl,Na2SO4,NaOH,NH3 on reaction will give CuCl2,CuSO4,Cu (OH)2,Cu(OH)2

Fe+3 with NaCl,Na2SO4,NaOH,NH3 on reaction will give FeCl3,Fe2(SO4)3,Fe(OH)3,Fe(OH)3

Mn+2 with NaCl,Na2SO4,NaOH,NH3 on reaction will give MnCl2,MnSO4,Mn(OH)2,Mn(OH)2

Ni+2 with NaCl,Na2SO4,NaOH,NH3 on reaction will give NiCl2,NiSO4,Ni(OH)2,Ni(OH)2

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.