x C Physics que IChegg.co G Account Help Self Service Center Wentworth Institute
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x C Physics que IChegg.co G Account Help Self Service Center Wentworth Institute of Tech Self Service Center Wiley PLUS O e edugen wiley dugen student mainfrun Wiley PLUS Halliday, Fundamentals of Physics, 10e Introductory Physics (PHYS 1303, 1304, 1307r 1308) Home Read, Study & Practice Assignment Gradebook ORION assignment open Assignment Chapter 23, Problem 034 Chapter 23 Proble In the figure a small cincular hole of radius R 1.87 cm has been cut in the middle of an infinite, fat, nonconducting surface that has a uniform charge density a 5.43 pc/m2. A z axis, with its origin at the hole's center, is perpendicular to the surface. What is the magnitude of the electric field at point P at z- 1.76 cm? (Hint see equation E- 2 R and use superposition Chapter 23, Prob Chapter 23, Prob 23, Prob Chapter 22, Prob Cha Number nits the tolerance is +/-1 in the 3rd significant digit 22 Prehiem Click if you would like to show Work for this question Open Shaw Work Review Score Question Attempts: o of 5 used SAVE FOR LATER SUBMIT ANSWER Review Results by Study objective Version 4.22.1.2 Licenac Agregment I Prisacy Polist I 2000-201Zlohn Wiley &Son; Inc. All Rights Reserved. A Division of lohn Mlay Sona Inc. PM ENG Ask me anything 2/18/2017Explanation / Answer
The radius of the circular hole R = 1.87 cm
= 1.87*10^-2 m
The surface charge density sigma = 5.43 pC/m^2
= 5.43*10^-12 C/m^2
The point z = 1.76 cm
= 1.76*10^-2 m
The electric filed due to circular disk at a perpendicular distance z
E = (sigma/2*e0)*[1-z/sqrt(z^2+R^2)]
= (5.43*10^-12/2*8.54*10^-12)*[1-1.76*10^-2/(1.76*10^-2^2+1.87*10^-2^2)]
= 0.3179*3.146
E = 0.10002 N/C
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