Q1: A layer of oil of 95 nm thickness floats on water. The oil has an index of r
ID: 1533267 • Letter: Q
Question
Q1:
A layer of oil of 95 nm thickness floats on water. The oil has an index of refraction of 1.4. A beam of wave incidents perpendicularly to the surface. What is the path difference of the two waves reflected from the front and back surfaces?
95 nm
95 nm/1.4
2 x 95 nm
95 nm/2
Q2:
A soap bubble has an index of refraction of 1.33. The thickness of this bubble is 99 nm. A beam of light has a wavelength of 530 nm in air. Show the ratio of path difference to the wavelength in the soap film. (Note the wavelength in the soap film is not equal to the wavelength in air.)
2 x 99 nm/1.33
(2 x 99 nm)/(530 nm/1.33)
99 nm/1.33
(530 nm/1.33)/(2 x 99 nm)
95 nm
95 nm/1.4
2 x 95 nm
95 nm/2
Q2:
A soap bubble has an index of refraction of 1.33. The thickness of this bubble is 99 nm. A beam of light has a wavelength of 530 nm in air. Show the ratio of path difference to the wavelength in the soap film. (Note the wavelength in the soap film is not equal to the wavelength in air.)
2 x 99 nm/1.33
(2 x 99 nm)/(530 nm/1.33)
99 nm/1.33
(530 nm/1.33)/(2 x 99 nm)
Explanation / Answer
Given
thickness of oil layer is t = 95 nm
refractive index of oil i s = 1.4
the path difference of the two waves reflected from the front and back is = 2*t = 2*95nm
the answer is 2*95 nm -------------->>> answer
Q2
given refractive index of soap bubble is ns = 1.33
thickness of bubble is t = 99 nm
light wavelength La = 530 nm
now the ratio of path difference to the wavelength in the soap film (Lf)
hee
the path difference is = 2*t = 2*99 nm
first wavelength in film is Lf = La/ns = 530/1.33
now ratio is = 2*99nm/(530/1.33) ----------------->>>>>>>> Answer
secons option is answer
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