Q16: I got this solution which is wrong but it was wrong. This is the x componen

Question

Q16:

I got this solution which is wrong but it was wrong.

This is the x component of the electric force. Is there also a magnetic force? N

Fx =

This is the x component of the electric force. Is there also a magnetic force? N

Fy = N Fz = N 16. + -18 points SerPSE9 29.P.059.MI.FB My Notes Ask Your Teacher A particle with positive charge q = 3.52 x 10-18 C moves with a velocity v- si + 2j-k) m/s through a region where both a uniform magnetic field and a uniform electric field exist (a) Calculate the total force on the moving particle, taking B- (sî + 2j+ k) Tand E taking B-(si.TandE-i--skvm (2î -1- 3 v/m. (b) What angle does the force vector make with the positive x axis?

Explanation / Answer

Electric force Fe = q*E = 3.52*10^-18*(2i-j-3k)
Fe = (7.04i-3.52j-10.56k)*10^-18

magnetic force FB = q*(v X B)

v X B = i(2+2)-j(5+5)+k(0)

v X B = 4i-10j

q*(v X B) = (14.08 i -35.2 j)*10^-18

Total force is Fnet = Fe+FB =( 21.12 i - 38.72 j -10.56 k)*10^-18

Fx = 21.12*10^-18 N

Fy = -38.72 *10^-18 N

Fz = -10.56*10^-18 N

B) required angle is

21.12*10^-18 = sqrt(21.12^2+38.72^2+10.56^2)*10^-18*1*cos(t)

cos (t) = 0.465
t = acos(0.465) = 62.3 degrees

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