Determine the acceleration from the position vs time graph. Take the slope of tw

Question

Determine the acceleration from the position vs time graph. Take the slope of two Worley spaced tangent lines. And use the definition of average acceleration to find the acceleration.

Time Position 0.034. 0.050 0.063 0.10 0.088 0.15 0.11. 0.2 0.13 .25 0.15. .3
Determine the acceleration from the position vs time graph. Take the slope of two Worley spaced tangent lines. And use the definition of average acceleration to find the acceleration.

Time Position 0.034. 0.050 0.063 0.10 0.088 0.15 0.11. 0.2 0.13 .25 0.15. .3


Time Position 0.034. 0.050 0.063 0.10 0.088 0.15 0.11. 0.2 0.13 .25 0.15. .3

Explanation / Answer

Here, v1 = (0.10 - 0.050)/(0.063 - 0.034)

                 = 1.724 m/s

v2 = (0.15 - 0.10)/(0.088 - 0.063)

      = 2 m/s

Thus,   average acceleration = (v2 - v1)/(t2 - t1)

                                               = (2 - 1.724)/(0.088 - 0.063)

                                              = 11.04 m/s2

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