A toy jeep rolls down an incline at a constant velocity. The jeep\'s mass is m =

Question

A toy jeep rolls down an incline at a constant velocity. The jeep's mass is m = 1.9 kg and the ramp makes an angle of theta = 13 with respect to the horizontal. Assume the rolling resistance is negligible. What is the magnitude of the jeep's acceleration a in m/s^2? a = What is the numeric value for the sum of the forces in the x-direction, sigma F_v in Newtons? Assuming the jeep experiences only air resistance in opposition to its motion, with magnitude F_r. Write an expression for the sum of the forces in the x-direction using the acceleration due to gravity, g, and the variables provided. What is the magnitude of the force caused by air resistance, F_r in Newtons? (Maintain the assumption that the jeep's velocity is constant.)

Explanation / Answer

a)Since t moves with constant acceleration,

a = 0

b)Since, a = 0, SumF = ma = 0

Hence, SumF = 0

c) mg cos(theta) - F = 0

.Fr = mg cos(theta)

d)Fr = mg cos(theta) = 1.9 x 9.8 x cos13 = 18.14 N

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