A planet orbits a star in an elliptical orbit. At a particular instant the momen

Question

A planet orbits a star in an elliptical orbit. At a particular instant the momentum of the planet is 3.6 1029, 1.1 1029, 0 kg · m/s, and the force on the planet by the star is 2.3 1022, 1.3 1023, 0 N. Find F and F . (Express your answers in vector form.) F = N F = N

An object moving at a constant speed of 40 m/s is making a turn with a radius of curvature of 3 m (this is the radius of the "kissing circle"). The object's momentum has a magnitude of 73 kg · m/s. What is the magnitude of the rate of change of the momentum?
|d /dt| =   [Correct: Your answer is correct.] kg · m/s2

What is the magnitude of the net force?
| net| =   [Incorrect: Your answer is incorrect.] N

Explanation / Answer

Velocity = v = 40 m/s

Distance = S = 2pi*r = 2pi*3 = 6pi

Time = S/v = 6pi/40 = 0.47 sec

Now the rate of change of the momentum = dp/dt = 73/0.47 = 154.9 kg · m/s2

the magnitude of the net force = F = dp/dt = 154.9 N

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