A battleship simultaneously fires two identical shells with the same initial spe

Question

A battleship simultaneously fires two identical shells with the same initial speed at enemy ships. If the shells follow the trajectories shown and hit the enemy ships at the same height above sea level, which shell has the greater final speed just before it hits the enemy ship? (Ignore air resistance.) shell A. Both have the same final speed. shell B Not enough information is given. A battleship simultaneously fires two identical shells with the same initial speed at enemy ships. If the shells follow the trajectories shown and hit the enemy ships at the same height above sea level, which shell has the larger kinetic energy just before it hits the enemy ship? (Ignore air resistance.) shell A. Both have the same final speed. shell B Not enough information is given.

Explanation / Answer

13) and 14) shell B

Explanation:

The time interval for the entire projectile motion is given by ttrip = trise + tfall = 2trise ,where trise is the rising time from 0 to the maximum height, and tfall the falling time from h to 0. In the absence of air resistance

trise = tfall

ttrip = 2*sqrt (2h/g)

So smaller h will have smaller ttrip. Means shell B has small ttrip and hence larger final velocity and kinetic energy.

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