A -4.00 nC point charge is at the origin, and a second -6.00 nC point charge is

Question

A -4.00 nC point charge is at the origin, and a second -6.00 nC point charge is on the x-axis at x = 0.800 m.

(just need help with these last 3 parts)

Part A Find the electric field (magnitude and direction) at point on the ar-axis at E 0.200 m. Express your answer with the appropriate units. Enter positive value if the field is in the positive direction and negative value if the field is in the negative r-direction 749 Submit My Answers Give Up Correct significant Figures Feedback: Your answer 750 was either rounded differently or used a different number of significant figures than required for this part.

Explanation / Answer

Here ,

q1= -4 nC

q2 = -6 nC

part A)

for the electric field at x = 0.2 m

electric field = k * q1/0.2^2 (-i) + k * q2/(0.8 - 0.2)^2 (i)

electric field = 9*10^9 * 10^-9 * (- 4/.2^2 + 6/.6^2)

electric field = -750 N/C

part B)

at the point x = 1.2 m

electric field = k * q1/1.2^2 (-i) + k * q2/(1.2 - 0.8)^2 (i)

electric field = 9*10^9 * 10^-9 * (- 4/1.2^2 - 6/.4^2)

electric field = -362.5 N/C

part c)

at the point x = -0.20 m

electric field = k * q1/0.2^2 (i) + k * q2/(0.2 + 0.8)^2 (i)

electric field = 9*10^9 * 10^-9 * ( 4/0.2^2 + 6/1^2)

electric field = 954 N/C

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