A snowmobile is originally at the point with position vector 31.5 m at 95.0° cou

Question

A snowmobile is originally at the point with position vector 31.5 m at 95.0° counterclockwise from the x axis, moving with velocity 4.37 m/s at 40.0°. It moves with constant acceleration 1.86 m/s2 at 200°. After 5.00 s have elapsed, find the following.

A snowmobile is originally at the point with position vector 29.1 m at 95.0° counterclockwise from the x axis, moving with velocity 4.49 m/s at 40.0°. It moves with constant acceleration 1.92 m/s2 at 200°. After 5.00 s have elapsed, find the following.

(a) its velocity vector

(b) its position vector

Explanation / Answer

The velocity vecotr will be:

v = (4.37 cos40 + 1.86 x cos200 x 5) i + (4.37 sin40 + 1.86 sin200 x 5)

v = (3.35 - 8.74 ) i + (2.81 - 3.18 ) = -5.39 i - 0.37 j

Hence, v = -5.39 i - 0.37 j

b)Position vector will be:

r = (31.5 cos95 + 4.37 x cos40 x 5 + 1/2 x 1.86 x cos200 x 5^2) i + (31.5 sin95 + 4.37 x sin40 x 5 + 1/2 x 1.86 x sin200 x5^2)

r = (-2.75 + 16.74 -21.85 )i + (31.38 + 14 -7.95)j = -7.86 i + 37.43 j

Hence, r = -7.86 i + 37.43 j

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