A particle has a charge of +3.2 C and moves from point A to point B , a distance

Question

A particle has a charge of +3.2 C and moves from point A to point B, a distance of 0.16 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.8 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

Chapter 19, Problem 04 GO

A particle has a charge of +3.2 C and moves from point A to point B, a distance of 0.16 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.8 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

Explanation / Answer

a)

we know that

F,dr = change in potential energy

F x 0.16 = 8.8 x 10^-4

F = 55 x 10^-4 N

b)

F = qE

E = F/q

E = 1718.75N/C

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