One strategy when on a diet is to drink ice water. The body must burn calories t
ID: 1528247 • Letter: O
Question
One strategy when on a diet is to drink ice water. The body must burn calories to warm the water from 0 degree C to a body temperature of 37 degree C. Assume a dieter drinks 2.9 kg (i.e. 2.9 L) of its water every day. The specific heat of water is 4.186 degree 10^3 J(kg middot degree C). Part (a) How much energy, in joules, does the dieter's body used to provide in order to warm the water over a full year. Take 365 days in a year. Part (b) One pound of fat supplies 2600 kcal(Cal) to the body, where 1 kcal(Cal) = 4.186 times 10^3 J. How much fat in pounds can be dieter do gain in a year by drinking ice water rather than water at body temperature? M = ____________Explanation / Answer
(A) Q = m C deltaT
Q = 2.9 x 4186 x (37 - 0)
Q = 12139.4 J
(b) energy required in a year = 365 x 12139.4 = 4.43 x 10^6 J
Q ( in k cal) = 1058.5 kCal
fat burned = 1058.5 / 3609 = 0.29 pounds
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