a hunter claims to have shot a charging bear through the heart and \" dropped hi

Question

a hunter claims to have shot a charging bear through the heart and " dropped him in his tracks." To immediately stop the bear, the momentum of the bullet would have to be as great as the momentum of the charging bear. Suppose the hunter was shooting one of the largest hunting rifles ever sold, a 0.50 caliber Sharps rifle, which delivers a 2.27 x 10-2 kg bullet at 376 m/s. Evaluate the hunters Claim by calculating the velocity of a250 kg bear after impact if he was initially moving directly toward the hunter at a slow 0.675 m/s (S)

Explanation / Answer

Applying momentum conservation for Bear - Bullet,

INitiallly momentum of bear plus bullet = final momentum of bear and bullet

(2.27 x 10^-2)(376) + (250 x -0.675) = (250 + 0.0227) vf

8.5352 - 168.75 = 250.0227 vf

vf = 0.64 m/s

hecne finally bear will be moving with 0.64 m/s toward the hunter.

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