Two point charges are placed on the x axis.(Figure 1) The first charge, Q1 = 8.0

Question

Two point charges are placed on the x axis.(Figure 1) The first charge, Q1 = 8.0 nC , is placed a distance x1 = 14 m from the origin along the positive x axis; the second charge, Q2 = 5.0 nC , is placed a distance x2 = 6.0 m from the origin along the negative x axis

A. Find the electric field at the origin, point O. FIND EOx and EOy

B. Now, assume that charge Q2 is negative; Q2=5.0 nC . (Figure 2) What is the net electric field at the origin, point O? FIND EOx and EOy

Figure 1

figure 2

Explanation / Answer

A.) Electric field = KQ/r^2

E = E1 +E2

E = KQ1/r^2 + KQ2/r^2

E = 9*10^9*8*10^-9/14^2 - 9*10^9*5*10^-9/6^2 = -0.74 N/C

B.)

Electric field = KQ/r^2

E = E1 +E2

E = KQ1/r^2 + KQ2/r^2

E = 9*10^9*8*10^-9/14^2 + 9*10^9*5*10^-9/6^2 = 1.61 N/C

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