Two point charges are placed on the x axis.(Figure 1) The first charge, q 1 = 8.

Question

Two point charges are placed on the x axis.(Figure 1) The first charge, q1 = 8.00nC , is placed a distance 16.0m from the origin along the positive x axis; the second charge, q2 = 6.00nC , is placed a distance 9.00m from the origin along the negative x axis.

Part A

Find the electric field at the origin, point O.

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive.

Part B

Now, assume that charge q2 is negative; q2=?6nC. (Figure 2) What is the net electric field at the origin, point O?

Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive.

EOx,EOy =

Explanation / Answer

Let a positive field be to the right so q1 will generate a + field and q2 a negative field

So E = k*(q1/r1^2 - q2/r2^2) = 9.0x10^9*(6.0x10^-9/9^2 - 8x10^-9/16^2) = 0.385 N/C

Part 2 Now both field point to the left so

E = k*(-q1/r1^2 - q2/r2^2) = 9.0x10^9*(-6.0x10^-9/9^2 - 8x10^-9/16^2) = -0.948 N/C

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