The proton is now removed from point B. Assume that the electric field at point

Question

The proton is now removed from point B. Assume that the electric field at point C is uniform and the space between the field lines at point C is 1/3 of what it is at point B. An electric dipole, made up of two particles. +4e and -4e separated by a distance of 16.8 nanometers, is now placed at point C. What is the magnitude of the torque on the dipole, if the angle between the dipole moment and the electric field at C is 28.0 degrees? (Note. Assume that the electric field is uniform over the dipole.) Give your answer in the form "a.bc times 10^(y) N.m".

Explanation / Answer

Torque, = pE sin

Where,

p - dipole moment

E - electric field

- angle between the dipole and the field

Also we have,

p = qd =4e x 16.8 x 109 = 4 x 1.6 x 10-19 x 16.8 x 109 = 10.75 x 10-9Cm

Now,

Torque, = pE sin = 10.75 x 10-9Cm x E x sin 28 = E x 5.04 x 10-9 Nm

Value of E is not there in the question.

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