While leaning out a window that is 5.7 m above the ground, you drop a 0.60-kg ba

Question

While leaning out a window that is 5.7 m above the ground, you drop a 0.60-kg basketball to a friend at ground level. Your friend catches the ball at a height of 1.5 m above the ground. Determine the following.

(a) the amount of work done by the force of gravity (_____J)

(b) the gravitational potential energy of the ball, relative to the ground when it is released (_____J)

(c) the gravitational potential energy of the ball, relative to the ground when it is caught (_____J) (d) the ratio of the change (PEf PE0) in the ball's gravitational potential energy to the work done on the ball by the force of gravity

Explanation / Answer

Answer a) the amount of work done by the force of gravity = (gravitational force)*(distance traveled in the direction of gravitational force) = Mg*(5.7-1.5) =0.60*9.8*4.2 = 24.696J

b) the gravitational potential energy of the ball, relative to the ground when it is released = Mg*(height above ground)= 0.60*9.8*5. 7= 33.516 J

C)the gravitational potential energy of the ball, relative to the ground when it is caught = Mg*(height above ground)= 0.60*9.8*1.5= 8.82 J

d) the ratio of the change (PEf PE0) in the ball's gravitational potential energy to the work done on the ball by the force of gravity = (33.516-8.82)/24.696 = 1

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.