A construction worker throws a hammer from the ground to his coworker 5m directl

Question

A construction worker throws a hammer from the ground to his coworker 5m directly above on a scaffold so the coworker doesn't have to climb down. If the hammer barely gets up there, how fast was the hammer initially thrown? (You may ignore rotations and air resistance.) You are at rest z = -1m and your friend is at rest at x = 1 m. At t = 5 seconds, you begin accelerating in the negative x direction at 1.0 m/s^2 on your high-powered scooter. At t = 10 seconds, your friend begins accelerating at 2.0 m/s^2 in the negative x direction on hers. When and where does your friend catch up with you?

Explanation / Answer

4. AT HIGHEST POINT , vf = 0

Applying vf^2 - vi^2 = 2 a d

0^2 - v^2 = 2 x -9.8 x 5

v = 9.90 m/s

5. after 10 sec,

d1 - (-1) = 0 x 10 + ( - 1 x (10 - 5)^2 ) / 2

d1 = - 13.5 m

v1 = 0 - 1 x 5 = - 5 m/s

for friend,

initial position = 1 m

after time t, they met hence

d = -13.5 + { -5t - 1 t^2 / 2} = 1 + { 0 - 2 t^2 / 2}

-14.5 - 5t - 0.5 t^2 = - t^2

0.5 t^2 - 5 t - 14.5 = 0

t = 12.35 sec

x = 1 + ( - 12.35^2 / 2 )

x = - 75.3 m ........Ans

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