In this example we will calculate the work done on an electron moving in a unifo

Question

In this example we will calculate the work done on an electron moving in a uniform electric field. Two large conducting plates separated by6.36 mm carry charges equal magnitude and opposite sign. creating a constant electric with magnitude 2.80 times 10^3 N/C between the plates An electron moves from the negatively charged plate to the positively charged plate. How mu Ch work does the electric field do on the electron? shows our sketch. The electric field is directed from the positive plate toward negate plate F rightarrow_E = q E rightarrow. so for an electron with negative charge q = -e, the electric force F rightarrow_E points in the direction opposite electric field. Its magnitude is F_E = e_E. The electro felids uniform so the to the force it exerts on the electron is constant during the electron's motion. The force and displacement are parallel the work w done by the electro-field force during a displacement of magnitude d is W= F_e d cos pi with pi = 0, so W = F_e d = e_ED =(1.60 times 10^19 C)(2.80 times 10^3 N/C) (6.36 times 10^-3 m) = 2.85 times 10^-18 J The amount of work done is proportional to the electric field magnitude E and to the displacement magnitude d of The electron. The electric field does positive work on If the electron. If there are no other forces, the electron's energy increases by the same amount as the work done on the electron by the electric field. in the same problem, how mu Ch work does the electric field do on the electron if the magnitude of the field is increased to 3.10 times 10^3 N/C and the separation between the plates is reduced to 361 mm ?

Explanation / Answer

part A)

work done due to electric field = force * seperation

work done due to electric field = e * E * distance

work done due to electric field = 1.602 * 10^-19 * 3.1 *10^3 * 3.612 *10^-3

work done due to electric field = 1.79 *10^-18 J

the work done due to electric field is 1.79 *10^-18 J

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