Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Multiple choice Answer Table (10pts each Question A B C D A B C D Multiple choic

ID: 1524881 • Letter: M

Question

Multiple choice Answer Table (10pts each Question A B C D A B C D Multiple choice: choose the best answer from the available choices in each question 1. A charged particle encounters a vertical uniform electric feld of 20 N/c y. The resulting force on the particle is 7 x 10 Ny (Neglect gravity) What is the charge of the article? a. 3.50 pc b, 2.86 x 10s c 3.50 uc d. 2.86 x 10 C 2. A solid spherical conductor has a radius o nd a total charge of 4 uc What is the magnitude of the electric field at a distance ero 25 m a W y from the conductors center a. 5.75 x 10 N/C c. 6.39 x 10 N/c d. 1.44 x 105 N/C 3. A particle with a charge of -7.25 uc is placed inside a parallel plate capacitor and experiences a net upward acceleration of 2.55 x 106 m/s If the mass of the particle is 1.0 grams, what is the surface charge density of the plate the charge is attracted to? b, 3.91 x 1018 C/m 3.11 x 103 c/m

Explanation / Answer

1. F = q E

7 x 10^-5 = q( -20)

q = - 3.5 x 10^-6 C = - 3.5 uC

2. field inside conductor is always zero.
Ans(b)


3. a = q E / m

2.55 x 10^-6 = (-7.25 x 10^-6) (E) / (1 x 10^-3)

E = 3.517 x 10^8 N/C

E = sigma / e0

sigma = (3.517 x 10^8) (8.852 x 10^-12) = 3.11 x 10^-3 C/m^2


4. surface charge density = 3.6 x 10^-11 / (0.023^2)

= 6.805 x 10^-8 C/m^2


E = sigma / e0 = 7686.12 N/C


a = q E / m = (1.602 x 10^-19) (7686.12) / (9.109 x 10^-27) = 1.352 x 10^16 m/s^2

v^2 - u^2 = 2 a d

(2 x10^6)^2 - 0 = 2 (1.352 x 10^15) (d)

d = 1.48 x 10^-3 m