ure https/feedugen.wleyplus.com/edugen/student/mainfr uni US Cutnell, Physics, 1

Question

ure https/feedugen.wleyplus.com/edugen/student/mainfr uni US Cutnell, Physics, 10e General Physics (General Physics Chapter 19, Problem Refer to solution us to review one way in which this problem can be solved. Two protons are moving drectly toward one another when they are very far apart, ther initial speeds are 2.00x m/s. What is the distance of closest approach? Units The number of signficant diges set to the tolerances --2% click if vou would like to show work for this question: Sasnahee Question Attempts o of s used SAVE ROR LATE. SUSHITANSMER 1/20/2017

Explanation / Answer

v = 2 x 10^2 m/s

PEi + KEi = PEf + KEf ( energy conservation )

0 + 2 ( m v^2 / 2) = k e^2 / d^2 + 0

(1.673 x 10^-27) (2 x 10^2)^2 = (9 x 10^9) (1.6 x 10^-19)^2 / d^2

d = 1.86 x 10^-3 m Or 1.86 mm

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