Resources Problem 2.38 An unmarked police car traveling a constant 85 km/h is pa

Question

Resources Problem 2.38 An unmarked police car traveling a constant 85 km/h is passed by a speeder traveling 137 km/h esources previous l 21 of 22 I next Part A Precisely 1.00 s after the speeder passes, the police officer steps on the accelerator: if the police car's acceleration is 2.30 m/s how much time passes after the police car is passed by a speeder and before the police car overtakes the speeder (assumed moving at constant speed)? Express your answer with the appropriate units. 4.55 Submit My Answers Give Up incorrect; Try Again; 2 attempts remaining Provide Feedback Continue kangaroo ju

Explanation / Answer

here

for police by using second equation of motion

x1 = v1 * t + 0.5 * a * t^2

for speedeer first equation of motin

x2 = v2 * (t + t0)

when police catches speeder , so x1 = x2

then

v1 * t + 0.5 * a * t^2 = v2 * t+ v2 * t0

0.5 * a * t^2 - (v2 - v1) * t - v2 * t0 = 0

0.5 * 2.3 * t^2 - (38.05 - 23.61) * t - 38.05 * 1=0......................................(137 km/hr =38.05m/s and 85km/hr = 23.61 m/s)

solve for t

t=14.79 s

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