Resources Problem 2.38 An unmarked police car traveling a constant 85 km/h is pa
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Resources Problem 2.38 An unmarked police car traveling a constant 85 km/h is passed by a speeder traveling 137 km/h esources previous l 21 of 22 I next Part A Precisely 1.00 s after the speeder passes, the police officer steps on the accelerator: if the police car's acceleration is 2.30 m/s how much time passes after the police car is passed by a speeder and before the police car overtakes the speeder (assumed moving at constant speed)? Express your answer with the appropriate units. 4.55 Submit My Answers Give Up incorrect; Try Again; 2 attempts remaining Provide Feedback Continue kangaroo juExplanation / Answer
We convert the units:
(85km/h)/(3.6ks/h) = 23.61 m/s.
(137km/h)/(3.6ks/h) = 38.06 m/s.
We use a coordinate system with the origin where the motorist passes the police officer.
The location of the speeding motorist is given by
xm = xo + vmt = 0 + (38.06 m/s)t.
The location of the police officer is given by
xp = xo + vop(1.00s) + vop(t - 1.00s) + 1/2ap(t< - 1.00s)2= 0 + (23.61 m/s)t + 1/2(2.3m/s2)(t - 1.00s)2.
e need to consider how much time passes while the distance decreases between the two cars. Since we do not know
the final speed of the police car when it overtakes the speeder, we need to consider the distance driven as it relates to
time. Consider the following equivalent statements:
distance driven by speeder = distance driven by police car
distance while driving faster than police + distance while driving slower than police = distance while driving slower
than speeder + distance while driving faster than speeder
distance while driving faster than police at constant speed+ distance while driving slower than police at constant
speed= distance while driving slower than speeder at constant speed+distance while driving slower than speeder with
acceleration+ distance while driving faster than speeder with acceleration
xm = xp;
(38.06m/s)t = (23.61m/s)t + 1/2(2.30m/s2)(t - 1.00s)2.
The solution to this quadratic equation
And find t
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