A drug molecule with polarizability alpha = 5.4x10-7 interacts with a cation wit

Question

A drug molecule with polarizability alpha = 5.4x10-7 interacts with a cation with the charge of 5x10-8 esu at a distance 0.8 nm. The charge creates electric field E = 0.5x10-8. The units of polarizability and electric field are compatible and generate the dipole moment in esu x nm in the drug molecule. What is electrostatic energy, in erg, of the interaction in the bilayer core (the dielectric constant = 2)? The result should be given with three decimal places, in the form X.XXX x 10-15. Enter only the part X.XXX.

THE ANSWER IS 1.055 X10^-15 I'M NOT SURE HOW TO SOLVE THIS PLEASE SHOW STEPS

Explanation / Answer

electrostatic energy = kq1q2/r

                                = (8.98 * 109 * 5x10-8 * 5.4x10-7)/(2.3 * 1011)

                                 = 1.055 * 10-15 erg

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