C Two Radio Antennas Sep x Chapter 27 Secure h ps://www.webassign.net/ web/Stude
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C Two Radio Antennas Sep x Chapter 27 Secure h ps://www.webassign.net/ web/Student/Assignment-Responses/submit?dep 5123403 Apps Y be 25 Yah M Inbox breanagancia2 L board Learn Duc San Diego Accoun X Code School-Try R G The wayward Hawaiia 5 Moves for Getti ti SHANY Professional 12. 04.76 points l Previous Answers SerPOP5 27.P 003 M My Notes Ask Your Teacher Ask Your Teacher Send Two radio antennas separated by d 270 m as shown in the figure below simultaneously broadcast identical signals at the same wavelength. A car travels due north along a straight line at position x 1 140 m from the center point between the antennas, and its radio receives the signals. Note: Do not use the smal angle approximation in this problem (a) If the car is at the position of the second maximum after that at point o when it has traveled a distance y 400 m northward, what is the wavelength of the signals Return to the derivation of the locations of constructive interference in Young's double slit experiment. m (b) How much farther must the car travel from this position to encounter the next minimum in reception? 125.85 You must work with the full trigonometric expressions for constructive and destructive interference because the angles are not small. m Need Help? Read it Master t 8-05 PM Ask me anything /20/2017Explanation / Answer
from the diagram
tan theta = y/x = 400/1140
theta = tan^-1 ( 400/1140)
=19.33
from the diffracion formula
d sin theta = m lamda
lamda = 270* sin 19.33/2 = 44.69 m
(b)
the formula for minimum is
d sin theta = ( m+ 1/2) lamda
for m=1
d sin theta = 5/2 * lamda
sin theta = 5 * lamda/ 2d= 5 * 44.69/ 2( 270)
sin theta= 0.413
theta = sin^-1 ( 0.413)
=24.44
tan theta = y min/11 40 m
y min = 1140* tan 24.44 = 518.26 m
The car will have to move additional 518.26 m -400 m=118.26 m
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